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x^2-3x-1120=0
a = 1; b = -3; c = -1120;
Δ = b2-4ac
Δ = -32-4·1·(-1120)
Δ = 4489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4489}=67$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-67}{2*1}=\frac{-64}{2} =-32 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+67}{2*1}=\frac{70}{2} =35 $
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